What are the solutions to the equation -3x^2+10x-3=0 ?

The solutions to the equation -3x^2+10x-3=0 are x= 1/3 ,x=3

Find the zeros of -3x^2+10x-3=0

The zeros of -3x^2+10x-3=0 are x= 1/3 ,x=3

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- 3 x^{2} + 10 x - 3 = 0

x = \frac{1}{3}, x = 3

Decimal Notation

x = 0.33333 \dots, x = 3

Solution steps

- 3 x^{2} + 10 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 3 ) ( - 3 )}{2 ( - 3 )}

1 0^{2} - 4 (- 3) (- 3) = 8

x_{1, 2} = \frac{- 10 \pm 8}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 10 + 8}{2 ( - 3 )}, x_{2} = \frac{- 10 - 8}{2 ( - 3 )}

x = \frac{- 10 + 8}{2 ( - 3 )} : \frac{1}{3}

x = \frac{- 10 - 8}{2 ( - 3 )} : 3

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = 3

x + 17 \leq - 3

(x - 1)^{2} + (1 - x) \times (x + 2) = 0

x^{2} - 7 x = 8

2.25 (\frac{1}{100})

(x + 1)^{2} = 25

What are the solutions to the equation -3x^2+10x-3=0 ?
The solutions to the equation -3x^2+10x-3=0 are x= 1/3 ,x=3
Find the zeros of -3x^2+10x-3=0
The zeros of -3x^2+10x-3=0 are x= 1/3 ,x=3