What is (x+1)(x-1)^2(x-3)<= 0 ?

The solution to (x+1)(x-1)^2(x-3)<= 0 is -1<= x<= 3

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(x+1)(x-1)^2(x-3)<= 0

(x + 1) (x - 1)^{2} (x - 3) \leq 0

- 1 \leq x \leq 3

Interval Notation

[- 1, 3]

Solution steps

(x + 1) (x - 1)^{2} (x - 3) \leq 0

Identify the intervals

- 1 \leq x \leq 3

\frac{0.39}{10} \cdot \frac{( 5 \cdot 9.81 )}{4 π}

4 x - \frac{1}{3} < 5 - 2 (3 - x)

2 x - 1 (5 - 3 x) = 4 x + 2

1029 y x^{3} + 24 y^{4}

- 3 = 3 x

What is (x+1)(x-1)^2(x-3)<= 0 ?
The solution to (x+1)(x-1)^2(x-3)<= 0 is -1<= x<= 3