What is (ln(2.1)-ln(2))/(2.1-2) ?

The solution to (ln(2.1)-ln(2))/(2.1-2) is (ln(1.05))/(0.1)

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simplify (ln(2.1)-ln(2))/(2.1-2)

simplify

\frac{ln ( 2.1 ) - ln ( 2 )}{2.1 - 2}

\frac{ln ( 1.05 )}{0.1}

Solution steps

\frac{ln ( 2.1 ) - ln ( 2 )}{2.1 - 2}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (2.1) - ln (2) = ln (\frac{2.1}{2})

= \frac{ln ( \frac{2.1}{2} )}{2.1 - 2}

Divide the numbers:

\frac{2.1}{2} = 1.05

= \frac{ln ( 1.05 )}{2.1 - 2}

Subtract the numbers:

2.1 - 2 = 0.1

= \frac{ln ( 1.05 )}{0.1}

lo g_{10} (x z^{8})

ln (9) - ln (6)

ln (5) + 2 ln (4)

3 lo g_{10} (a) + lo g_{10} (c)

2 ln (8) - ln (4)

What is (ln(2.1)-ln(2))/(2.1-2) ?
The solution to (ln(2.1)-ln(2))/(2.1-2) is (ln(1.05))/(0.1)