What are the solutions to the equation m^2+6m-7=0 ?

The solutions to the equation m^2+6m-7=0 are m=1,m=-7

Find the zeros of m^2+6m-7=0

The zeros of m^2+6m-7=0 are m=1,m=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 6 m - 7 = 0

m = 1, m = - 7

Solution steps

m^{2} + 6 m - 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 7) = 8

m_{1, 2} = \frac{- 6 \pm 8}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 6 + 8}{2 \cdot 1}, m_{2} = \frac{- 6 - 8}{2 \cdot 1}

m = \frac{- 6 + 8}{2 \cdot 1} : 1

m = \frac{- 6 - 8}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

m = 1, m = - 7

- 5.5 x + 0.56 = - 1.64

∣ x - 8 ∣ \geq 5

y + 4 z + 5 x - 3 y + 5 z

12 = k \cdot 2

\frac{3}{2} + \frac{1}{2}

What are the solutions to the equation m^2+6m-7=0 ?
The solutions to the equation m^2+6m-7=0 are m=1,m=-7
Find the zeros of m^2+6m-7=0
The zeros of m^2+6m-7=0 are m=1,m=-7