What is log_{10}(1215x^{0.84}) ?

The solution to log_{10}(1215x^{0.84}) is log_{10}(1215)+0.84log_{10}(x)

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simplify log_{10}(1215x^{0.84})

simplify

lo g_{10} (1215 x^{0.84})

lo g_{10} (1215) + 0.84 lo g_{10} (x)

Solution steps

lo g_{10} (1215 x^{0.84})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (1215 x^{0.84}) = lo g_{10} (1215) + lo g_{10} (x^{0.84})

= lo g_{10} (1215) + lo g_{10} (x^{0.84})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (x^{0.84}) = 0.84 lo g_{10} (x)

= lo g_{10} (1215) + 0.84 lo g_{10} (x)

ln (x) - 3 ln (z) + 0.5 ln (y)

lo g_{10} (x^{5} y^{3} z)

lo g_{10} (\frac{x}{w})

ln (1 \cdot 1 0^{- 3})

ln (100) - ln (101)

What is log_{10}(1215x^{0.84}) ?
The solution to log_{10}(1215x^{0.84}) is log_{10}(1215)+0.84log_{10}(x)