What is 0.65log_{10}(0.39x)+1.45 ?

The solution to 0.65log_{10}(0.39x)+1.45 is 0.65log_{10}(39)+0.65log_{10}(x)+0.15

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simplify 0.65log_{10}(0.39x)+1.45

simplify

0.65 lo g_{10} (0.39 x) + 1.45

0.65 lo g_{10} (39) + 0.65 lo g_{10} (x) + 0.15

Solution steps

0.65 lo g_{10} (0.39 x) + 1.45

Simplify

0.65 lo g_{10} (0.39 x) : 0.65 lo g_{10} (39) + 0.65 lo g_{10} (x) - 1.3

= 0.65 lo g_{10} (39) + 0.65 lo g_{10} (x) - 1.3 + 1.45

Add the numbers:

- 1.3 + 1.45 = 0.15

= 0.65 lo g_{10} (39) + 0.65 lo g_{10} (x) + 0.15

ln (\frac{200}{100})

ln (5 \cdot e^{7})

- lo g_{10} (2.8 \cdot 1 0^{- 8})

ln (\frac{103}{80})

ln ((1 - 1 0^{- 5}) 600)

What is 0.65log_{10}(0.39x)+1.45 ?
The solution to 0.65log_{10}(0.39x)+1.45 is 0.65log_{10}(39)+0.65log_{10}(x)+0.15