What is expand ln((2x+1)(x-4)) ?

The solution to expand ln((2x+1)(x-4)) is ln(2x+1)+ln(x-4)

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expand ln((2x+1)(x-4))

expand

ln ((2 x + 1) (x - 4))

ln (2 x + 1) + ln (x - 4)

Solution steps

ln ((2 x + 1) (x - 4))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln ((2 x + 1) (x - 4)) = ln (2 x + 1) + ln (x - 4)

= ln (2 x + 1) + ln (x - 4)

ln (2 cos (\frac{x}{2}))

ln (3 - 2 x) - 2 ln (x)

ln (\frac{2}{72})

f (b) = ln (4 b)

ln (\frac{e ^{x}}{x})

What is expand ln((2x+1)(x-4)) ?
The solution to expand ln((2x+1)(x-4)) is ln(2x+1)+ln(x-4)