What is log_{10}((150)/(3.6))+1.9 ?

The solution to log_{10}((150)/(3.6))+1.9 is log_{10}(150)-log_{10}(3.6)+1.9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}((150)/(3.6))+1.9

simplify

lo g_{10} (\frac{150}{3.6}) + 1.9

lo g_{10} (150) - lo g_{10} (3.6) + 1.9

Decimal Notation

3.51978 \dots

Solution steps

lo g_{10} (\frac{150}{3.6}) + 1.9

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{150}{3.6}) = lo g_{10} (150) - lo g_{10} (3.6)

= lo g_{10} (150) - lo g_{10} (3.6) + 1.9

ln (x + 1) - 2 ln (x - 1)

ln (- 1) - ln (2)

ln (31) - ln (132)

- lo g_{10} (7 \cdot 1 0^{- 3})

ln (\frac{a}{2}) - ln (a)

What is log_{10}((150)/(3.6))+1.9 ?
The solution to log_{10}((150)/(3.6))+1.9 is log_{10}(150)-log_{10}(3.6)+1.9