What is ln(y^2+5)-ln(y^2-2) ?

The solution to ln(y^2+5)-ln(y^2-2) is ln((y^2+5)/(y^2-2))

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simplify ln(y^2+5)-ln(y^2-2)

simplify

ln (y^{2} + 5) - ln (y^{2} - 2)

ln (\frac{y ^{2} + 5}{y ^{2} - 2})

Solution steps

ln (y^{2} + 5) - ln (y^{2} - 2)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (y^{2} + 5) - ln (y^{2} - 2) = ln (\frac{y ^{2} + 5}{y ^{2} - 2})

= ln (\frac{y ^{2} + 5}{y ^{2} - 2})

lo g_{6} (\frac{1}{120})

x + ln (x) + ln (2)

\frac{ln ( x ) - ln ( 3 )}{x - 3}

27.7 ln (\frac{142}{x})

- lo g_{10} (9.5 \cdot 1 0^{- 12})

What is ln(y^2+5)-ln(y^2-2) ?
The solution to ln(y^2+5)-ln(y^2-2) is ln((y^2+5)/(y^2-2))