What is ln(r^2+1)-ln(r^2-1) ?

The solution to ln(r^2+1)-ln(r^2-1) is ln((r^2+1)/(r^2-1))

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simplify ln(r^2+1)-ln(r^2-1)

simplify

ln (r^{2} + 1) - ln (r^{2} - 1)

ln (\frac{r ^{2} + 1}{r ^{2} - 1})

Solution steps

ln (r^{2} + 1) - ln (r^{2} - 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (r^{2} + 1) - ln (r^{2} - 1) = ln (\frac{r ^{2} + 1}{r ^{2} - 1})

= ln (\frac{r ^{2} + 1}{r ^{2} - 1})

- 3 ln (\frac{- 3}{9})

6.1 + lo g_{10} (\frac{13}{1.2})

5 ln (u) - ln (v)

2 x^{3} - 5 ln (+ 3 cos (x))

- lo g_{10} (0.2 \cdot 1 0^{- 3})

What is ln(r^2+1)-ln(r^2-1) ?
The solution to ln(r^2+1)-ln(r^2-1) is ln((r^2+1)/(r^2-1))