What is ln(1)+ln(2)+ln(3)+ln(4) ?

The solution to ln(1)+ln(2)+ln(3)+ln(4) is ln(24)

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simplify ln(1)+ln(2)+ln(3)+ln(4)

simplify

ln (1) + ln (2) + ln (3) + ln (4)

ln (24)

Decimal Notation

3.17805 \dots

Solution steps

ln (1) + ln (2) + ln (3) + ln (4)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (2) + ln (3) = ln (2 \cdot 3)

= ln (1) + ln (2 \cdot 3) + ln (4)

Multiply the numbers:

2 \cdot 3 = 6

= ln (1) + ln (6) + ln (4)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (6) + ln (4) = ln (6 \cdot 4)

= ln (1) + ln (6 \cdot 4)

Multiply the numbers:

6 \cdot 4 = 24

= ln (1) + ln (24)

Apply log rule:

lo g_{a} (1) = 0

= 0 + ln (24)

0 + ln (24) = ln (24)

= ln (24)

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- lo g_{10} (2.5 \cdot 1 0^{- 13})

What is ln(1)+ln(2)+ln(3)+ln(4) ?
The solution to ln(1)+ln(2)+ln(3)+ln(4) is ln(24)