What is expand log_{12}(n/(19)) ?

The solution to expand log_{12}(n/(19)) is log_{12}(n)-log_{12}(19)

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expand log_{12}(n/(19))

expand

lo g_{12} (\frac{n}{19})

lo g_{12} (n) - lo g_{12} (19)

Solution steps

lo g_{12} (\frac{n}{19})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{12} (\frac{n}{19}) = lo g_{12} (n) - lo g_{12} (19)

= lo g_{12} (n) - lo g_{12} (19)

ln (\frac{x - 0}{x - 1})

ln (\frac{x - 1}{- x - 1})

lo g_{e} (\frac{1}{2}) - 1

ln (33) - ln (23)

ln (\frac{11 x + 3}{7 x ^{2} + 2 x - 9})

What is expand log_{12}(n/(19)) ?
The solution to expand log_{12}(n/(19)) is log_{12}(n)-log_{12}(19)