What is log_{10}(log_{4}(164x)1.024) ?

The solution to log_{10}(log_{4}(164x)1.024) is log_{10}(log_{4}(164x))+log_{10}(1.024)

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simplify log_{10}(log_{4}(164x)1.024)

simplify

lo g_{10} (lo g_{4} (164 x) 1.024)

lo g_{10} (lo g_{4} (164 x)) + lo g_{10} (1.024)

Solution steps

lo g_{10} (lo g_{4} (164 x) \cdot 1.024)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (lo g_{4} (164 x) \cdot 1.024) = lo g_{10} (lo g_{4} (164 x)) + lo g_{10} (1.024)

= lo g_{10} (lo g_{4} (164 x)) + lo g_{10} (1.024)

ln (\frac{x + y}{x})

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ln (1.8 \cdot 10 e^{- 5})

- ln (\frac{1}{1 + e ^{- x}})

What is log_{10}(log_{4}(164x)1.024) ?
The solution to log_{10}(log_{4}(164x)1.024) is log_{10}(log_{4}(164x))+log_{10}(1.024)