What is log_{e}((2x-1)/(x-1)) ?

The solution to log_{e}((2x-1)/(x-1)) is ln(2x-1)-ln(x-1)

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simplify log_{e}((2x-1)/(x-1))

simplify

lo g_{e} (\frac{2 x - 1}{x - 1})

ln (2 x - 1) - ln (x - 1)

Solution steps

lo g_{e} (\frac{2 x - 1}{x - 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{e} (\frac{2 x - 1}{x - 1}) = lo g_{e} (2 x - 1) - lo g_{e} (x - 1)

= lo g_{e} (2 x - 1) - lo g_{e} (x - 1)

Apply log rule:

lo g_{e} (x) = ln (x)

= ln (2 x - 1) - lo g_{e} (x - 1)

Apply log rule:

lo g_{e} (x) = ln (x)

= ln (2 x - 1) - ln (x - 1)

lo g_{e} (0.4 p) - lo g_{e} (p)

3 [2 ln (x - 1) - ln (x)] + ln (x + 1)

\frac{1}{8} ln (2)

ln (0.00006) - ln (0.00022)

ln (\frac{x - y}{y})

What is log_{e}((2x-1)/(x-1)) ?
The solution to log_{e}((2x-1)/(x-1)) is ln(2x-1)-ln(x-1)