What is 3log_{10}(a-1)+log_{10}(a+2) ?

The solution to 3log_{10}(a-1)+log_{10}(a+2) is log_{10}((a-1)^3(a+2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 3log_{10}(a-1)+log_{10}(a+2)

simplify

3 lo g_{10} (a - 1) + lo g_{10} (a + 2)

lo g_{10} ((a - 1)^{3} (a + 2))

Solution steps

3 lo g_{10} (a - 1) + lo g_{10} (a + 2)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 lo g_{10} (a - 1) = lo g_{10} ((a - 1)^{3})

= lo g_{10} ((a - 1)^{3}) + lo g_{10} (a + 2)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} ((a - 1)^{3}) + lo g_{10} (a + 2) = lo g_{10} ((a - 1)^{3} (a + 2))

= lo g_{10} ((a - 1)^{3} (a + 2))

2 (ln (2) - ln (3))

ln (tan (y) tan (x))

ln (\frac{15.88}{6.67})

- lo g_{10} (5.011 \cdot 1 0^{- 9})

ln (\frac{185}{200})

What is 3log_{10}(a-1)+log_{10}(a+2) ?
The solution to 3log_{10}(a-1)+log_{10}(a+2) is log_{10}((a-1)^3(a+2))