What is ((u^{-1}v^2)^2)/((u^3v^{-2))^3} ?

The solution to ((u^{-1}v^2)^2)/((u^3v^{-2))^3} is (v^{10})/(u^{11)}

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simplify ((u^{-1}v^2)^2)/((u^3v^{-2))^3}

simplify

\frac{( u ^{- 1} v ^{2} ) ^{2}}{( u ^{3} v ^{- 2} ) ^{3}}

\frac{v ^{10}}{u ^{11}}

Solution steps

\frac{( u ^{- 1} v ^{2} ) ^{2}}{( u ^{3} v ^{- 2} ) ^{3}}

Simplify

(u^{- 1} v^{2})^{2} : \frac{v ^{4}}{u ^{2}}

= \frac{\frac{v ^{4}}{u ^{2}}}{( u ^{3} v ^{- 2} ) ^{3}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{v ^{4}}{u ^{2} ( u ^{3} v ^{- 2} ) ^{3}}

Simplify

u^{2} (u^{3} v^{- 2})^{3} : \frac{u ^{11}}{v ^{6}}

= \frac{v ^{4}}{\frac{u ^{11}}{v ^{6}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{v ^{4} v ^{6}}{u ^{11}}

Simplify

v^{4} v^{6} : v^{10}

= \frac{v ^{10}}{u ^{11}}

0 \cdot x = 0

- π > - 3

3 x^{2} + 2 = 0

- \frac{3}{15}

2 x^{3} - 3 x^{2} + 4 x - 6

What is ((u^{-1}v^2)^2)/((u^3v^{-2))^3} ?
The solution to ((u^{-1}v^2)^2)/((u^3v^{-2))^3} is (v^{10})/(u^{11)}