What are the solutions to the equation 3x^2+2=0 ?

The solutions to the equation 3x^2+2=0 are x=sqrt(2/3)i,x=-sqrt(2/3)i

Find the zeros of 3x^2+2=0

The zeros of 3x^2+2=0 are x=sqrt(2/3)i,x=-sqrt(2/3)i

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3 x^{2} + 2 = 0

x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

3 x^{2} + 2 = 0

Move

2

to the right side

3 x^{2} = - 2

Divide both sides by

3

x^{2} = - \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{2}{3}, x = - - \frac{2}{3}

- \frac{2}{3} = \frac{2}{3} i

- - \frac{2}{3} = - \frac{2}{3} i

x = \frac{2}{3} i, x = - \frac{2}{3} i

- \frac{3}{15}

2 x^{3} - 3 x^{2} + 4 x - 6

\frac{4}{24} = \frac{c}{36}

17 > \frac{239}{58}

12 x^{4} + 10 x^{3} - 12 x^{2}

What are the solutions to the equation 3x^2+2=0 ?
The solutions to the equation 3x^2+2=0 are x=sqrt(2/3)i,x=-sqrt(2/3)i
Find the zeros of 3x^2+2=0
The zeros of 3x^2+2=0 are x=sqrt(2/3)i,x=-sqrt(2/3)i