What is (ln(7))/(3ln(3)-2ln(7)) ?

The solution to (ln(7))/(3ln(3)-2ln(7)) is (ln(7))/(ln(27/49))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (ln(7))/(3ln(3)-2ln(7))

simplify

\frac{ln ( 7 )}{3 ln ( 3 ) - 2 ln ( 7 )}

\frac{ln ( 7 )}{ln ( \frac{27}{49} )}

Decimal Notation

- 3.26504 \dots

Solution steps

\frac{ln ( 7 )}{3 ln ( 3 ) - 2 ln ( 7 )}

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 ln (3) = ln (3^{3})

= \frac{ln ( 7 )}{ln ( 3 ^{3} ) - 2 ln ( 7 )}

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 ln (7) = ln (7^{2})

= \frac{ln ( 7 )}{ln ( 3 ^{3} ) - ln ( 7 ^{2} )}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (3^{3}) - ln (7^{2}) = ln (\frac{3 ^{3}}{7 ^{2}})

= \frac{ln ( 7 )}{ln ( \frac{3 ^{3}}{7 ^{2}} )}

\frac{3 ^{3}}{7 ^{2}} = \frac{27}{49}

= \frac{ln ( 7 )}{ln ( \frac{27}{49} )}

ln (\frac{2 e ^{x}}{3 x})

ln (R e^{iπ})

lo g_{9} (- 3 x) + lo g_{9} (- 10 x)

3 ln (4) - ln (16) + ln (3)

\frac{2}{5} lo g_{10} (778)

What is (ln(7))/(3ln(3)-2ln(7)) ?
The solution to (ln(7))/(3ln(3)-2ln(7)) is (ln(7))/(ln(27/49))