What is ln(y^2+4)-ln(y^2-2) ?

The solution to ln(y^2+4)-ln(y^2-2) is ln((y^2+4)/(y^2-2))

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simplify ln(y^2+4)-ln(y^2-2)

simplify

ln (y^{2} + 4) - ln (y^{2} - 2)

ln (\frac{y ^{2} + 4}{y ^{2} - 2})

Solution steps

ln (y^{2} + 4) - ln (y^{2} - 2)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (y^{2} + 4) - ln (y^{2} - 2) = ln (\frac{y ^{2} + 4}{y ^{2} - 2})

= ln (\frac{y ^{2} + 4}{y ^{2} - 2})

ln (x^{- 1}) - ln (3)

ln (\frac{0.692}{0.0112})

ln (\frac{505}{760})

\frac{1}{2} ln (y) - ln (x)

3 ln (2 e)

What is ln(y^2+4)-ln(y^2-2) ?
The solution to ln(y^2+4)-ln(y^2-2) is ln((y^2+4)/(y^2-2))