What are the solutions to the equation 0=x^2-4x-2 ?

The solutions to the equation 0=x^2-4x-2 are x=2+sqrt(6),x=2-sqrt(6)

Find the zeros of 0=x^2-4x-2

The zeros of 0=x^2-4x-2 are x=2+sqrt(6),x=2-sqrt(6)

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0 = x^{2} - 4 x - 2

x = 2 + 6, x = 2 - 6

Decimal

x = 4.44948 \dots, x = - 0.44948 \dots

Solution steps

0 = x^{2} - 4 x - 2

Switch sides

x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 2) = 26

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 6}{2 \cdot 1} : 2 + 6

x = \frac{- ( - 4 ) - 2 6}{2 \cdot 1} : 2 - 6

The solutions to the quadratic equation are:

x = 2 + 6, x = 2 - 6

x^{2} - 20 x + 100

5 x^{3} - 30 x^{2} + 25 x

π \cdot 1 0^{2}

x^{2} - 16 x + 60 = 0

- 6 x + 16 > 24 - 4 x

What are the solutions to the equation 0=x^2-4x-2 ?
The solutions to the equation 0=x^2-4x-2 are x=2+sqrt(6),x=2-sqrt(6)
Find the zeros of 0=x^2-4x-2
The zeros of 0=x^2-4x-2 are x=2+sqrt(6),x=2-sqrt(6)