What is 2(ln(1+e^5)-ln(1+e)) ?

The solution to 2(ln(1+e^5)-ln(1+e)) is 2ln((1+e^5)/(1+e))

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simplify 2(ln(1+e^5)-ln(1+e))

simplify

2 (ln (1 + e^{5}) - ln (1 + e))

2 ln (\frac{1 + e ^{5}}{1 + e})

Solution steps

2 (ln (1 + e^{5}) - ln (1 + e))

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (1 + e^{5}) - ln (1 + e) = ln (\frac{e ^{5} + 1}{e + 1})

= 2 ln (\frac{1 + e ^{5}}{1 + e})

ln (x + 2) - ln (x)

- lo g_{10} (8 \cdot 1 0^{- 10})

ln (γ (a))

20 lo g_{10} (\frac{2}{π})

ln (\frac{3}{x ^{2} + 1})

What is 2(ln(1+e^5)-ln(1+e)) ?
The solution to 2(ln(1+e^5)-ln(1+e)) is 2ln((1+e^5)/(1+e))