What is 2log_{7}(x+1)+log_{7}(3) ?

The solution to 2log_{7}(x+1)+log_{7}(3) is log_{7}((x+1)^2*3)

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simplify 2log_{7}(x+1)+log_{7}(3)

simplify

2 lo g_{7} (x + 1) + lo g_{7} (3)

lo g_{7} ((x + 1)^{2} \cdot 3)

Solution steps

2 lo g_{7} (x + 1) + lo g_{7} (3)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{7} (x + 1) = lo g_{7} ((x + 1)^{2})

= lo g_{7} ((x + 1)^{2}) + lo g_{7} (3)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{7} ((x + 1)^{2}) + lo g_{7} (3) = lo g_{7} (3 (x + 1)^{2})

= lo g_{7} ((x + 1)^{2} \cdot 3)

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What is 2log_{7}(x+1)+log_{7}(3) ?
The solution to 2log_{7}(x+1)+log_{7}(3) is log_{7}((x+1)^2*3)