What is ln(0.5263x)+0.9ln(0.4737x) ?

The solution to ln(0.5263x)+0.9ln(0.4737x) is ln(0.26864…x^{1.9})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln(0.5263x)+0.9ln(0.4737x)

simplify

ln (0.5263 x) + 0.9 ln (0.4737 x)

ln (0.26864 \dots x^{1.9})

Solution steps

ln (0.5263 x) + 0.9 ln (0.4737 x)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

0.9 ln (0.4737 x) = ln ((0.4737 x)^{0.9})

= ln (0.5263 x) + ln ((0.4737 x)^{0.9})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (0.5263 x) + ln ((0.4737 x)^{0.9}) = ln (0.5263 x (0.4737 x)^{0.9})

= ln (0.5263 x (0.4737 x)^{0.9})

Simplify

0.5263 x (0.4737 x)^{0.9} : 0.26864 \dots x^{1.9}

= ln (0.26864 \dots x^{1.9})

ln (v y)

ln^{5} (+ 1 ln (y) - 7 ln (x))

ln (\frac{2 x ^{3} - 2}{x + 1})

- 6 ln (2 y)

lo g_{2} (\frac{5}{200})

What is ln(0.5263x)+0.9ln(0.4737x) ?
The solution to ln(0.5263x)+0.9ln(0.4737x) is ln(0.26864…x^{1.9})