What is 2log_{6}(w-2)-3log_{6}(w)+9 ?

The solution to 2log_{6}(w-2)-3log_{6}(w)+9 is log_{6}(((w-2)^2)/(w^3))+9

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simplify 2log_{6}(w-2)-3log_{6}(w)+9

simplify

2 lo g_{6} (w - 2) - 3 lo g_{6} (w) + 9

lo g_{6} (\frac{( w - 2 ) ^{2}}{w ^{3}}) + 9

Solution steps

2 lo g_{6} (w - 2) - 3 lo g_{6} (w) + 9

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{6} (w - 2) = lo g_{6} ((w - 2)^{2})

= lo g_{6} ((w - 2)^{2}) - 3 lo g_{6} (w) + 9

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 lo g_{6} (w) = lo g_{6} (w^{3})

= lo g_{6} ((w - 2)^{2}) - lo g_{6} (w^{3}) + 9

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{6} ((w - 2)^{2}) - lo g_{6} (w^{3}) = lo g_{6} (\frac{( w - 2 ) ^{2}}{w ^{3}})

= lo g_{6} (\frac{( w - 2 ) ^{2}}{w ^{3}}) + 9

ln (12) + 8 x + 5 - ln (3)

ln (4 e 4)

ln (\frac{2 ^{2}}{3 ( 4 ^{3} )})

ln (\frac{2 \cdot 2}{3 \cdot 2})

ln (\frac{x}{( 3 - x )})

What is 2log_{6}(w-2)-3log_{6}(w)+9 ?
The solution to 2log_{6}(w-2)-3log_{6}(w)+9 is log_{6}(((w-2)^2)/(w^3))+9