What is 4log_{10}(z)-log_{10}(x) ?

The solution to 4log_{10}(z)-log_{10}(x) is log_{10}((z^4)/x)

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simplify 4log_{10}(z)-log_{10}(x)

simplify

4 lo g_{10} (z) - lo g_{10} (x)

lo g_{10} (\frac{z ^{4}}{x})

Solution steps

4 lo g_{10} (z) - lo g_{10} (x)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{10} (z) = lo g_{10} (z^{4})

= lo g_{10} (z^{4}) - lo g_{10} (x)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (z^{4}) - lo g_{10} (x) = lo g_{10} (\frac{z ^{4}}{x})

= lo g_{10} (\frac{z ^{4}}{x})

20 ln (\frac{87}{34})

ln (n θ^{2 n} x e^{- θ n x})

ln (a - b) - ln (a)

- ln (y) - ln (c)

ln (\frac{9}{7 ^{4} 8})

What is 4log_{10}(z)-log_{10}(x) ?
The solution to 4log_{10}(z)-log_{10}(x) is log_{10}((z^4)/x)