What is ln(((e^{2.8214}+1))/2) ?

The solution to ln(((e^{2.8214}+1))/2) is ln(e^{2.8214}+1)-ln(2)

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simplify ln(((e^{2.8214}+1))/2)

simplify

ln (\frac{( e ^{2.8214} + 1 )}{2})

ln (e^{2.8214} + 1) - ln (2)

Solution steps

ln (\frac{( e ^{2.8214} + 1 )}{2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{( e ^{2.8214} + 1 )}{2}) = ln ((e^{2.8214} + 1)) - ln (2)

= ln (e^{2.8214} + 1) - ln (2)

lo g_{10} (1 0^{- 6} \cdot 20)

3 ln (2) - 3 ln (2 + 1)

ln (\frac{a ^{2}}{b ^{- 3} c ^{2}})

ln (\frac{10000}{8600})

ln (x^{3}) + ln (y)

What is ln(((e^{2.8214}+1))/2) ?
The solution to ln(((e^{2.8214}+1))/2) is ln(e^{2.8214}+1)-ln(2)