What is (ln(2))/(ln(3)+ln(2)) ?

The solution to (ln(2))/(ln(3)+ln(2)) is (ln(2))/(ln(6))

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simplify (ln(2))/(ln(3)+ln(2))

simplify

\frac{ln ( 2 )}{ln ( 3 ) + ln ( 2 )}

\frac{ln ( 2 )}{ln ( 6 )}

Solution steps

\frac{ln ( 2 )}{ln ( 3 ) + ln ( 2 )}

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (3) + ln (2) = ln (3 \cdot 2)

= \frac{ln ( 2 )}{ln ( 3 \cdot 2 )}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{ln ( 2 )}{ln ( 6 )}

lo g_{10} (\frac{- 5}{x + 8})

ln (x) - \frac{1}{4} ln (v^{2} + 2)

ln (255 sin^{2} (x))

ln (\frac{30}{8.51})

lo g_{3} (\frac{5}{e})

What is (ln(2))/(ln(3)+ln(2)) ?
The solution to (ln(2))/(ln(3)+ln(2)) is (ln(2))/(ln(6))