What is log_{y}((1+x)/(1-2)) ?

The solution to log_{y}((1+x)/(1-2)) is log_{y}(1+x)-log_{y}(-1)

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simplify log_{y}((1+x)/(1-2))

simplify

lo g_{y} (\frac{1 + x}{1 - 2})

lo g_{y} (1 + x) - lo g_{y} (- 1)

Solution steps

lo g_{y} (\frac{1 + x}{1 - 2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{y} (\frac{1 + x}{1 - 2}) = lo g_{y} (1 + x) - lo g_{y} (1 - 2)

= lo g_{y} (x + 1) - lo g_{y} (1 - 2)

Subtract the numbers:

1 - 2 = - 1

= lo g_{y} (x + 1) - lo g_{y} (- 1)

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What is log_{y}((1+x)/(1-2)) ?
The solution to log_{y}((1+x)/(1-2)) is log_{y}(1+x)-log_{y}(-1)