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Popular >

simplify 2ln(v-1)-ln(v+1)

Solution

simplify

2 ln (v - 1) - ln (v + 1)

Solution

ln (\frac{( v - 1 ) ^{2}}{v + 1})

Solution steps

2 ln (v - 1) - ln (v + 1)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 ln (v - 1) = ln ((v - 1)^{2})

= ln ((v - 1)^{2}) - ln (v + 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ((v - 1)^{2}) - ln (v + 1) = ln (\frac{( v - 1 ) ^{2}}{v + 1})

= ln (\frac{( v - 1 ) ^{2}}{v + 1})

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Frequently Asked Questions (FAQ)

What is 2ln(v-1)-ln(v+1) ?
The solution to 2ln(v-1)-ln(v+1) is ln(((v-1)^2)/(v+1))