What are the solutions to the equation 0=2x^2+x-6 ?

The solutions to the equation 0=2x^2+x-6 are x= 3/2 ,x=-2

Find the zeros of 0=2x^2+x-6

The zeros of 0=2x^2+x-6 are x= 3/2 ,x=-2

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0 = 2 x^{2} + x - 6

x = \frac{3}{2}, x = - 2

Decimal

x = 1.5, x = - 2

Solution steps

0 = 2 x^{2} + x - 6

Switch sides

2 x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 6) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 2}, x_{2} = \frac{- 1 - 7}{2 \cdot 2}

x = \frac{- 1 + 7}{2 \cdot 2} : \frac{3}{2}

x = \frac{- 1 - 7}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 2

1.8 \cdot 1 0^{- 5} = \frac{x ^{2}}{0.25}

(64 b) \frac{3}{4}

8 w (6 - w) + 3 (w - 6)

6 x^{2} + 66 x + 168

- \frac{5}{4} y - 7 = \frac{1}{2} y - \frac{7}{3}

What are the solutions to the equation 0=2x^2+x-6 ?
The solutions to the equation 0=2x^2+x-6 are x= 3/2 ,x=-2
Find the zeros of 0=2x^2+x-6
The zeros of 0=2x^2+x-6 are x= 3/2 ,x=-2