What is factor 3x^3+26x^2+64x+32 ?

The solution to factor 3x^3+26x^2+64x+32 is (3x+2)(x+4)^2

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factor 3x^3+26x^2+64x+32

factor

3 x^{3} + 26 x^{2} + 64 x + 32

(3 x + 2) (x + 4)^{2}

Solution steps

3 x^{3} + 26 x^{2} + 64 x + 32

Use the rational root theorem

= (3 x + 2) \frac{3 x ^{3} + 26 x ^{2} + 64 x + 32}{3 x + 2}

\frac{3 x ^{3} + 26 x ^{2} + 64 x + 32}{3 x + 2} = x^{2} + 8 x + 16

= (3 x + 2) (x^{2} + 8 x + 16)

Factor

x^{2} + 8 x + 16 : (x + 4) (x + 4)

= (3 x + 2) (x + 4) (x + 4)

Apply exponent rule:

aa = a^{2}

(x + 4) (x + 4) = (x + 4)^{2}

= (3 x + 2) (x + 4)^{2}

4 n^{2} - 4 n + 1

82 + 25 - 52

8 (z + 3) = 32

10 y^{2} + 9 y + 2

- 6 = \frac{3}{8} x

What is factor 3x^3+26x^2+64x+32 ?
The solution to factor 3x^3+26x^2+64x+32 is (3x+2)(x+4)^2