What is log_{x}(-2log_{10}(x-1)) ?

The solution to log_{x}(-2log_{10}(x-1)) is log_{x}(2)+log_{x}(log_{10}(x-1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{x}(-2log_{10}(x-1))

simplify

lo g_{x} (- 2 lo g_{10} (x - 1))

lo g_{x} (2) + lo g_{x} (lo g_{10} (x - 1))

Solution steps

lo g_{x} (- 2 lo g_{10} (x - 1))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{x} (- 2 lo g_{10} (x - 1)) = lo g_{x} (2) + lo g_{x} (lo g_{10} (x - 1))

= lo g_{x} (2) + lo g_{x} (lo g_{10} (x - 1))

ln (\frac{1.81}{0.498})

ln (x - 68) - ln (x + 14)

1.6 \cdot ln (0.9 n)

ln (8 (2) + 3) - ln (8 (0) + 3)

ln (3 i^{- i})

What is log_{x}(-2log_{10}(x-1)) ?
The solution to log_{x}(-2log_{10}(x-1)) is log_{x}(2)+log_{x}(log_{10}(x-1))