What is ln(n^3+8)-ln(9n^3+19n) ?

The solution to ln(n^3+8)-ln(9n^3+19n) is ln((n^3+8)/(9n^3+19n))

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simplify ln(n^3+8)-ln(9n^3+19n)

simplify

ln (n^{3} + 8) - ln (9 n^{3} + 19 n)

ln (\frac{n ^{3} + 8}{9 n ^{3} + 19 n})

Solution steps

ln (n^{3} + 8) - ln (9 n^{3} + 19 n)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (n^{3} + 8) - ln (9 n^{3} + 19 n) = ln (\frac{n ^{3} + 8}{9 n ^{3} + 19 n})

= ln (\frac{n ^{3} + 8}{9 n ^{3} + 19 n})

- lo g_{10} (1.34 \cdot 1 0^{- 7})

- ln (x) - ln (v - 1)

ln (\frac{5 - x}{x ^{2} + x - 6})

ln (8) - ln (x) - 4 ln (5) + 2 ln (y)

4186 ln (\frac{323}{373})

What is ln(n^3+8)-ln(9n^3+19n) ?
The solution to ln(n^3+8)-ln(9n^3+19n) is ln((n^3+8)/(9n^3+19n))