What is 3ln(1.75)-ln(-0.5)+ln(-1)+6 ?

The solution to 3ln(1.75)-ln(-0.5)+ln(-1)+6 is ln(10.71875)+6

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simplify 3ln(1.75)-ln(-0.5)+ln(-1)+6

simplify

3 ln (1.75) - ln (- 0.5) + ln (- 1) + 6

ln (10.71875) + 6

Solution steps

3 ln (1.75) - ln (- 0.5) + ln (- 1) + 6

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 ln (1.75) = ln (1.7 5^{3})

= ln (1.7 5^{3}) - ln (- 0.5) + ln (- 1) + 6

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (1.7 5^{3}) - ln (- 0.5) = ln (\frac{1.7 5 ^{3}}{- 0.5})

= ln (\frac{1.7 5 ^{3}}{- 0.5}) + ln (- 1) + 6

\frac{1.7 5 ^{3}}{- 0.5} = - 10.71875

= ln (- 10.71875) + ln (- 1) + 6

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (- 10.71875) + ln (- 1) = ln (- (- 1) \cdot 10.71875)

= ln (- (- 1) \cdot 10.71875) + 6

- 10.71875 (- 1) = 10.71875

= ln (10.71875) + 6

\frac{ln ^{2} ( 2 e ) - ln ( 2 )}{2}

- lo g_{10} (4.1 \cdot 1 0^{- 9})

1 ln (x) - \frac{5}{2} ln (y)

6.1 + lo g_{10} (\frac{28}{2.3})

ln (\frac{488}{4798})

What is 3ln(1.75)-ln(-0.5)+ln(-1)+6 ?
The solution to 3ln(1.75)-ln(-0.5)+ln(-1)+6 is ln(10.71875)+6