What is ln(e^{x^3})-ln(x^4-7x+1) ?

The solution to ln(e^{x^3})-ln(x^4-7x+1) is ln((e^{x^3})/(x^4-7x+1))

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simplify ln(e^{x^3})-ln(x^4-7x+1)

simplify

ln (e^{x^{3}}) - ln (x^{4} - 7 x + 1)

ln (\frac{e ^{x^{3}}}{x ^{4} - 7 x + 1})

Solution steps

ln (e^{x^{3}}) - ln (x^{4} - 7 x + 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (e^{x^{3}}) - ln (x^{4} - 7 x + 1) = ln (\frac{e ^{x^{3}}}{x ^{4} - 7 x + 1})

= ln (\frac{e ^{x^{3}}}{x ^{4} - 7 x + 1})

4 [ln (x) - ln (x + 7) - ln (x - 7)]

ln (\frac{x c}{m})

4 ln (9 x) + 4

7 ln (7) (ln (6) - ln (2))

4 ln (6) - 4 ln (3)

What is ln(e^{x^3})-ln(x^4-7x+1) ?
The solution to ln(e^{x^3})-ln(x^4-7x+1) is ln((e^{x^3})/(x^4-7x+1))