What is simplify-log_{10}(1x10^{-8}) ?

The solution to simplify-log_{10}(1x10^{-8}) is -log_{10}(x)+8

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simplify-log_{10}(1x10^{-8})

simplify

- lo g_{10} (1 x 1 0^{- 8})

- lo g_{10} (x) + 8

Solution steps

- lo g_{10} (1 \cdot x \cdot 1 0^{- 8})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (1 \cdot x \cdot 1 0^{- 8}) = lo g_{10} (1) + lo g_{10} (x) + lo g_{10} (1 0^{- 8})

= - (lo g_{10} (x) + lo g_{10} (1) + lo g_{10} (1 0^{- 8}))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (1 0^{- 8}) = - 8 lo g_{10} (10)

= - (lo g_{10} (1) + lo g_{10} (x) - 8 lo g_{10} (10))

lo g_{10} (1) = 0

8 lo g_{10} (10) = 8

= - (lo g_{10} (x) + 0 - 8)

Simplify

0 + lo g_{10} (x) - 8 : lo g_{10} (x) - 8

= - (lo g_{10} (x) - 8)

Distribute parentheses

= - (lo g_{10} (x)) - (- 8)

Apply minus-plus rules

- (- a) = a, - (a) = - a

= - lo g_{10} (x) + 8

c^{x} - ln (c^{x}) + ln (x)

ln (\frac{c}{e ^{4 x}})

ln (\frac{c - x}{c + y})

\frac{1}{2} ln (17)

- lo g_{10} (4.56 \cdot 1 0^{- 5})

What is simplify-log_{10}(1x10^{-8}) ?
The solution to simplify-log_{10}(1x10^{-8}) is -log_{10}(x)+8