What is (ln(x-1)-ln(x+1))/2 ?

The solution to (ln(x-1)-ln(x+1))/2 is (ln((x-1)/(x+1)))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (ln(x-1)-ln(x+1))/2

simplify

\frac{ln ( x - 1 ) - ln ( x + 1 )}{2}

\frac{ln ( \frac{x - 1}{x + 1} )}{2}

Solution steps

\frac{ln ( x - 1 ) - ln ( x + 1 )}{2}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (x - 1) - ln (x + 1) = ln (\frac{x - 1}{x + 1})

= \frac{ln ( \frac{x - 1}{x + 1} )}{2}

ln (\frac{x - 5}{x - 3})

ln (csc (θ)) + ln (tan (θ))

ln (n^{2} + 3) - ln (2 n^{2} - 1)

ln (- 2) + ln (- 5)

ln (\frac{x}{61 \cdot 1 0 ^{- 6}})

What is (ln(x-1)-ln(x+1))/2 ?
The solution to (ln(x-1)-ln(x+1))/2 is (ln((x-1)/(x+1)))/2