What are the solutions to the equation 8w^2+2w+2=3 ?

The solutions to the equation 8w^2+2w+2=3 are w= 1/4 ,w=-1/2

Find the zeros of 8w^2+2w+2=3

The zeros of 8w^2+2w+2=3 are w= 1/4 ,w=-1/2

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8 w^{2} + 2 w + 2 = 3

w = \frac{1}{4}, w = - \frac{1}{2}

Decimal Notation

w = 0.25, w = - 0.5

Solution steps

8 w^{2} + 2 w + 2 = 3

Move

3

to the left side

8 w^{2} + 2 w - 1 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

2^{2} - 4 \cdot 8 (- 1) = 6

w_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 8}

Separate the solutions

w_{1} = \frac{- 2 + 6}{2 \cdot 8}, w_{2} = \frac{- 2 - 6}{2 \cdot 8}

w = \frac{- 2 + 6}{2 \cdot 8} : \frac{1}{4}

w = \frac{- 2 - 6}{2 \cdot 8} : - \frac{1}{2}

The solutions to the quadratic equation are:

w = \frac{1}{4}, w = - \frac{1}{2}

lo g_{9} (3) + lo g_{9} (27)

x^{2} - 3 x - 10 \geq 0

4 m^{2} - 25 = 0

\frac{x y - x - y + 1}{x ^{2} + 9 x - 10}

(x + 8)^{2} = 16

What are the solutions to the equation 8w^2+2w+2=3 ?
The solutions to the equation 8w^2+2w+2=3 are w= 1/4 ,w=-1/2
Find the zeros of 8w^2+2w+2=3
The zeros of 8w^2+2w+2=3 are w= 1/4 ,w=-1/2