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Popular >

simplify ln(c^1)+0.8*ln(c^2)

Solution

simplify

ln (c^{1}) + 0.8 \cdot ln (c^{2})

Solution

ln (c^{2.6})

Solution steps

ln (c^{1}) + 0.8 ln (c^{2})

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

0.8 ln (c^{2}) = ln ((c^{2})^{0.8})

= ln (c^{1}) + ln ((c^{2})^{0.8})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (c^{1}) + ln ((c^{2})^{0.8}) = ln (c^{1} (c^{2})^{0.8})

= ln (c^{1} (c^{2})^{0.8})

Simplify

c^{1} (c^{2})^{0.8} : c^{2.6}

= ln (c^{2.6})

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Frequently Asked Questions (FAQ)

What is ln(c^1)+0.8*ln(c^2) ?
The solution to ln(c^1)+0.8*ln(c^2) is ln(c^{2.6})