What is ln(y^2+2)-ln(y^2-2) ?

The solution to ln(y^2+2)-ln(y^2-2) is ln((y^2+2)/(y^2-2))

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simplify ln(y^2+2)-ln(y^2-2)

simplify

ln (y^{2} + 2) - ln (y^{2} - 2)

ln (\frac{y ^{2} + 2}{y ^{2} - 2})

Solution steps

ln (y^{2} + 2) - ln (y^{2} - 2)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (y^{2} + 2) - ln (y^{2} - 2) = ln (\frac{y ^{2} + 2}{y ^{2} - 2})

= ln (\frac{y ^{2} + 2}{y ^{2} - 2})

- lo g_{10} (3.37 \cdot 1 0^{- 6})

ln ((3 x + 2)^{x s i n (x)})

ln (3 (10))

e n^{l n (9) - l n (7)}

4 (ln (z) + ln (z + 5) - 2 ln (z - 5))

What is ln(y^2+2)-ln(y^2-2) ?
The solution to ln(y^2+2)-ln(y^2-2) is ln((y^2+2)/(y^2-2))