What is ln(z^2+1)-ln(z^2-2) ?

The solution to ln(z^2+1)-ln(z^2-2) is ln((z^2+1)/(z^2-2))

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simplify ln(z^2+1)-ln(z^2-2)

simplify

ln (z^{2} + 1) - ln (z^{2} - 2)

ln (\frac{z ^{2} + 1}{z ^{2} - 2})

Solution steps

ln (z^{2} + 1) - ln (z^{2} - 2)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (z^{2} + 1) - ln (z^{2} - 2) = ln (\frac{z ^{2} + 1}{z ^{2} - 2})

= ln (\frac{z ^{2} + 1}{z ^{2} - 2})

ln (\frac{0.4697}{0.4411})

- lo g_{10} (6.3 \cdot 1 0^{- 7})

ln (\frac{b b a}{c})

ln (\frac{x ^{3}}{x ^{2} + 1})

\frac{1}{2} ln (- 2)

What is ln(z^2+1)-ln(z^2-2) ?
The solution to ln(z^2+1)-ln(z^2-2) is ln((z^2+1)/(z^2-2))