What is 1/2 (ln(y-1)-ln(y+1)) ?

The solution to 1/2 (ln(y-1)-ln(y+1)) is 1/2 ln((y-1)/(y+1))

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simplify 1/2 (ln(y-1)-ln(y+1))

simplify

\frac{1}{2} (ln (y - 1) - ln (y + 1))

\frac{1}{2} ln (\frac{y - 1}{y + 1})

Solution steps

\frac{1}{2} (ln (y - 1) - ln (y + 1))

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (y - 1) - ln (y + 1) = ln (\frac{y - 1}{y + 1})

= \frac{1}{2} ln (\frac{y - 1}{y + 1})

ln (3^{2}) + ln (2^{7})

ln (\frac{200}{215})

5 ln (4) - 6 ln (3) - 2

ln (x^{5} \cdot e^{- 3 x})

lo g_{e} (\frac{1}{a ^{2}})

What is 1/2 (ln(y-1)-ln(y+1)) ?
The solution to 1/2 (ln(y-1)-ln(y+1)) is 1/2 ln((y-1)/(y+1))