What is expand-log_{9}((3-x)^2) ?

The solution to expand-log_{9}((3-x)^2) is -2log_{9}(3-x)

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expand-log_{9}((3-x)^2)

expand

- lo g_{9} ((3 - x)^{2})

- 2 lo g_{9} (3 - x)

Solution steps

- lo g_{9} ((3 - x)^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{9} ((3 - x)^{2}) = 2 lo g_{9} (3 - x)

= - 2 lo g_{9} (3 - x)

- lo g_{10} (6.31 \cdot 1 0^{- 3})

ln (\frac{0.010668}{0.007112})

ln (2 e) (\frac{5}{33})

ln (3 e^{2 θ})

5 ln (3) + 5 ln (3) + 5 ln (2)

What is expand-log_{9}((3-x)^2) ?
The solution to expand-log_{9}((3-x)^2) is -2log_{9}(3-x)