What is 0.5[ln(1-0.68)-ln(1+0.68)] ?

The solution to 0.5[ln(1-0.68)-ln(1+0.68)] is 0.5ln(0.19047…)

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simplify 0.5[ln(1-0.68)-ln(1+0.68)]

simplify

0.5 [ln (1 - 0.68) - ln (1 + 0.68)]

0.5 ln (0.19047 \dots)

Decimal Notation

- 0.82911 \dots

Solution steps

0.5 [ln (1 - 0.68) - ln (1 + 0.68)]

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (1 - 0.68) - ln (1 + 0.68) = ln (\frac{1 - 0.68}{1 + 0.68})

= 0.5 [ln (\frac{1 - 0.68}{1 + 0.68})]

\frac{1 - 0.68}{1 + 0.68} = 0.19047 \dots

= 0.5 [ln (0.19047 \dots)]

Remove parentheses:

(a) = a

= 0.5 ln (0.19047 \dots)

ln (b \cdot e^{- c \cdot x})

lo g_{e} (3 e^{- x})

ln (4 x^{b} x^{c} x^{1 - b - c})

3 ln (2) - 3 ln (3)

ln (x^{2}) - ln (y)

What is 0.5[ln(1-0.68)-ln(1+0.68)] ?
The solution to 0.5[ln(1-0.68)-ln(1+0.68)] is 0.5ln(0.19047…)