What is ln(z^2+5)-ln(z^2-5) ?

The solution to ln(z^2+5)-ln(z^2-5) is ln((z^2+5)/(z^2-5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln(z^2+5)-ln(z^2-5)

simplify

ln (z^{2} + 5) - ln (z^{2} - 5)

ln (\frac{z ^{2} + 5}{z ^{2} - 5})

Solution steps

ln (z^{2} + 5) - ln (z^{2} - 5)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (z^{2} + 5) - ln (z^{2} - 5) = ln (\frac{z ^{2} + 5}{z ^{2} - 5})

= ln (\frac{z ^{2} + 5}{z ^{2} - 5})

ln (2 x - 1) - ln (2 x + 1)

ln (\frac{125}{3})

ln (\frac{2400}{3000})

- lo g_{10} (50 \cdot 0.1)

ln (\frac{178500}{130000})

What is ln(z^2+5)-ln(z^2-5) ?
The solution to ln(z^2+5)-ln(z^2-5) is ln((z^2+5)/(z^2-5))