What is e^{ln(2x)}e^9+ln(20x) ?

The solution to e^{ln(2x)}e^9+ln(20x) is 2e^9x+ln(20)+ln(x)

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simplify e^{ln(2x)}e^9+ln(20x)

simplify

e^{l n (2 x)} e^{9} + ln (20 x)

2 e^{9} x + ln (20) + ln (x)

Solution steps

e^{l n (2 x)} e^{9} + ln (20 x)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (20 x) = ln (20) + ln (x)

= e^{9} e^{l n (2 x)} + ln (20) + ln (x)

Simplify

e^{l n (2 x)} : 2 x

= 2 e^{9} x + ln (20) + ln (x)

ln (\frac{2 ^{2}}{3 ^{4} 5 ^{3}})

2 ln (x) + ln (z)

- lo g_{10} (2.95 \cdot 1 0^{- 2})

ln (cot (x) \cdot e^{x})

ln (x - 3) + ln (x - 6)

What is e^{ln(2x)}e^9+ln(20x) ?
The solution to e^{ln(2x)}e^9+ln(20x) is 2e^9x+ln(20)+ln(x)