What is cos(xy)+e^{yz}+ln(xz) ?

The solution to cos(xy)+e^{yz}+ln(xz) is cos(xy)+e^{yz}+ln(x)+ln(z)

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simplify cos(xy)+e^{yz}+ln(xz)

simplify

cos (x y) + e^{yz} + ln (x z)

cos (x y) + e^{yz} + ln (x) + ln (z)

Solution steps

cos (x y) + e^{yz} + ln (x z)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (x z) = ln (x) + ln (z)

= cos (x y) + e^{yz} + ln (x) + ln (z)

\frac{ln ( 3 ) - 5 ln ( 2 )}{4 ln ( 2 )}

ln (- 2 c)

ln (\frac{2 x + 1}{1 - 2 x})

ln (1 + x y) + ln (1 - z)

\frac{1}{4} \cdot ln (3)

What is cos(xy)+e^{yz}+ln(xz) ?
The solution to cos(xy)+e^{yz}+ln(xz) is cos(xy)+e^{yz}+ln(x)+ln(z)