What is expand ln((2x+1)^{1/(ln(x))}) ?

The solution to expand ln((2x+1)^{1/(ln(x))}) is (ln(2x+1))/(ln(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ln((2x+1)^{1/(ln(x))})

expand

ln ((2 x + 1)^{\frac{1}{l n ( x )}})

\frac{ln ( 2 x + 1 )}{ln ( x )}

Solution steps

ln ((2 x + 1)^{\frac{1}{l n ( x )}})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln ((2 x + 1)^{\frac{1}{l n ( x )}}) = \frac{1}{ln ( x )} ln (2 x + 1)

= \frac{1}{ln ( x )} ln (2 x + 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ln ( 2 x + 1 )}{ln ( x )}

Multiply:

1 \cdot ln (2 x + 1) = ln (2 x + 1)

= \frac{ln ( 2 x + 1 )}{ln ( x )}

2 ln (x) + ln (x) + ln (y)

ln (\frac{14}{25})

ln (x x^{2} + 9)

ln (\frac{11.5}{20.5})

2 ln (a) + 3 ln (b) - 4 ln (c)

What is expand ln((2x+1)^{1/(ln(x))}) ?
The solution to expand ln((2x+1)^{1/(ln(x))}) is (ln(2x+1))/(ln(x))