What is ln(1/((1+s^w)^{x+1)}) ?

The solution to ln(1/((1+s^w)^{x+1)}) is -ln(s^w+1)(x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln(1/((1+s^w)^{x+1)})

simplify

ln (\frac{1}{( 1 + s ^{w} ) ^{x + 1}})

- ln (s^{w} + 1) (x + 1)

Solution steps

ln (\frac{1}{( 1 + s ^{w} ) ^{x + 1}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1}{( 1 + s ^{w} ) ^{x + 1}}) = ln (1) - ln ((1 + s^{w})^{x + 1})

= ln (1) - ln ((s^{w} + 1)^{x + 1})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln ((1 + s^{w})^{x + 1}) = (x + 1) ln (1 + s^{w})

= ln (1) - (x + 1) ln (1 + s^{w})

Apply log rule:

lo g_{a} (1) = 0

= 0 - ln (s^{w} + 1) (x + 1)

0 - (x + 1) ln (1 + s^{w}) = - (x + 1) ln (1 + s^{w})

= - ln (s^{w} + 1) (x + 1)

ln (4 x^{- 2})

ln (\frac{7.41}{12})

ln (\frac{0.35}{0.86})

ln (a b^{\frac{1}{2}})

ln (a (e^{x} - 1))

What is ln(1/((1+s^w)^{x+1)}) ?
The solution to ln(1/((1+s^w)^{x+1)}) is -ln(s^w+1)(x+1)