What is log_{10}(e^{-x}cos(pix)) ?

The solution to log_{10}(e^{-x}cos(pix)) is -xlog_{10}(e)+log_{10}(cos(pix))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}(e^{-x}cos(pix))

simplify

lo g_{10} (e^{- x} cos (π x))

- x lo g_{10} (e) + lo g_{10} (cos (π x))

Solution steps

lo g_{10} (e^{- x} cos (π x))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (e^{- x} cos (π x)) = lo g_{10} (e^{- x}) + lo g_{10} (cos (π x))

= lo g_{10} (e^{- x}) + lo g_{10} (cos (π x))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (e^{- x}) = - x lo g_{10} (e)

= - x lo g_{10} (e) + lo g_{10} (cos (π x))

2 - 2 ln (2) + 2 ln (x)

lo g_{10} (810) + lo g_{10} (0.03)

- \frac{1}{3} (ln (26) - ln (5))

ln (\frac{1}{t})

ln ∣ 4 ∣ - ln (x)

What is log_{10}(e^{-x}cos(pix)) ?
The solution to log_{10}(e^{-x}cos(pix)) is -xlog_{10}(e)+log_{10}(cos(pix))